Given that two of the zeroes of the cubic polynomial ax 3

 + bx 2 + cx + d are 0, the third zero is

(a) (-b)/a        (b) b/a  (c) c/a    (d) -d/a

Two of the zeroes of the cubic polynomial ax^3  + bx^2 + cx + d are 0 - MCQs from NCERT Exemplar

part 2 - Question 2 - MCQs from NCERT Exemplar - Serial order wise - Chapter 2 Class 10 Polynomials

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Question 2 Given that two of the zeroes of the cubic polynomial ax3 + bx2 + cx + d are 0, the third zero is (a) (−𝑏)/𝑎 (b) 𝑏/𝑎 (c) 𝑐/𝑎 (d) −𝑑/𝑎 Let p(x) = ax3 + bx2 + cx + d Given that two zeroes are 0 ∴ 𝜶 = 0, 𝜷 = 0 and we need to find 𝜸 We know that Sum of zeroes = (−𝒃)/𝒂 𝜶 + 𝜷 + 𝜸 = (−𝑏)/𝑎 0 + 0 + 𝜸 = (−𝑏)/𝑎 𝜸 = (−𝑏)/𝑎 𝜶 + 𝛽 + 𝛾 = (−𝑏)/𝑎 0 + 0 + 𝛾 = (−𝑏)/𝑎 𝜸 = (−𝒃)/𝒂 Thus, the third zero is (−𝑏)/𝑎 So, the correct answer is (A)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo