Ex 9.3, 12 - Chapter 9 Class 9 Circles

Last updated at July 26, 2026 by

Ex 9.3, 12 - Prove that cyclic parallelogram is a rectangle - Ex 9.3

part 2 - Ex 9.3, 12 - Ex 9.3 - Serial order wise - Chapter 9 Class 9 Circles

 

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Ex 9.3, 12 Prove that a cyclic parallelogram is a rectangle. Given: Let ABCD be a cyclic parallelogram To prove: ABCD is a rectangle Proof: A rectangle is a parallelogram with one angle 90 So, we have to prove angle 90 Since ABCD is a parallelogram A = C In cyclic parallelogram ABCD A + C = 180 A + A = 180 2 A = 180 A = (180 )/2 = 90 So, ABCD is a parallelogram with one angle 90 Hence, ABCD is a rectangle

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