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Ex 1.2, 3 Prove that the following are irrationals : (iii) 6 + √2 We have to prove 6 + √2 is irrational Let us assume the opposite, i.e., 6 + √𝟐 is rational Hence, 6 + √2 can be written in the form 𝑎/𝑏 where a and b (b≠ 0) are co-prime (no common factor other than 1) Hence, 6 + √𝟐 = 𝒂/𝒃 √2 = 𝑎/𝑏 − 6 √𝟐 = (𝒂 − 𝟔𝒃)/𝒃 Here, (𝑎 −6𝑏)/𝑏 is a rational number But √5 is irrational Since, Rational ≠ Irrational This is a contradiction ∴ Our assumption is incorrect Therefore, 6 + √𝟐 is irrational Hence proved.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.