The product of two consecutive positive integers is 306. We need to

Ex 4.1, 2 (ii) - Chapter 4 Class 10 Quadratic Equations - Part 2

  1. Chapter 4 Class 10 Quadratic Equations (Term 2)
  2. Serial order wise

Transcript

Ex 4.1 ,2 Represent the following situations in the form of quadratic equations : (ii) The product of two consecutive positive integers is 306. We need to find the integers. There is a difference of 1 in consecutive integers, Hence, Let the first integer = x Second integer = x + 1 Now , given that Product of integers = 306 First integer Second integer = 306 x (x + 1) = 306 x2 + x = 306 x2 + x 306 = 0 It is the form of ax2 + bx + c = 0 Where a = 1, b = 1 , c = 306 Hence, it is a quadratic equation .

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.