Ex 2.2, 2 (i) - Find p(0), p(1) and p(2) for p(y) = y^2 - y + 1 - Ex 2.2

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Ex 2.2, 2 Find p(0) , p(1) and p(2) for each of the following polynomials (i) ๐‘(y)=๐‘ฆ^2โˆ’๐‘ฆ+1 Given ๐’‘(๐ฒ)=๐’š^๐Ÿโˆ’๐’š+๐Ÿ Putting ๐’š=๐ŸŽ ๐’‘(๐ŸŽ)=0^2โˆ’0+1 =0โˆ’0+1 =๐Ÿ Putting ๐’š=๐Ÿ ๐’‘(๐Ÿ)=1^2โˆ’1+1 =1โˆ’1+1 =๐Ÿ Putting ๐’š=๐Ÿ ๐’‘(๐Ÿ)=2^2โˆ’2+1 =4โˆ’2+1 =2+1 =๐Ÿ‘

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