NCERT Additional Question 3
Last updated at April 16, 2024 by Teachoo
Additional Excercises
Last updated at April 16, 2024 by Teachoo
Additional Question 3 A hammer of mass 500 g, moving at 50 m sβ1, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer? Given Mass of hammer = m = 500 g = 500/1000 kg = 0.5 kg Initial velocity of the hammer = u = 50 m/s Time taken as 0.03 instead of 0.01 Since the hammer comes to rest, Final velocity of hammer = v = 0 m/s We know that Force = (π (π£ β π’))/π‘ = (0.5 (0 β 50))/0.01 = (0.5 Γ β50)/0.03 = (5/10 Γ β50)/(3/100) = (5 Γ β50 Γ 100)/(10 Γ 3) = β2500 N This is the Force exerted by Hammer on the nail β΄ Hammer strikes the nail with a force of β2500 N. By Newtonβs third law of motion, nail exerts an equal force in opposite direction on the hammer β΄ Force exerted by nail on hammer = 2500 N