# NCERT Question 18 - Chapter 9 Class 9 - Force and Laws Of Motion

Last updated at June 7, 2019 by Teachoo

Last updated at June 7, 2019 by Teachoo

Transcript

NCERT Question 18 How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 m s–2. NCERT Question 18 How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 m s–2. Now, Momentum = Mass × Velocity = m × v ∴ We need v to calculate momentum We have u, a and s, Finding v using 3rd equation of motion. v2 − u2 = 2as v2 − (0) 2 = 2 × 10 × 0.8 v2 = 16 v = ± √16 v = ± 4 m/s Since the acceleration is positive, ∴ Velocity increases So, we take positive value of v Thus, v = 4 m/s Now, Momentum = m × v = 10 × 4 = 40 kg m/s

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NCERT Question 18 You are here

Class 9

Chapter 9 Class 9 - Force and Laws Of Motion

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.