In right angle triangle ABC, 8 cm, 15 cm and 17 cm are the length of AB,BC and CA respectively. Then, find out sinA,cosA and tanA

AB = 8 cm, BC = 15 cm, AC = 17 cm

According to the diagram,

AB = Adjacent Side, BC = Opposite Side, AC = Hypotenuse.

Now we need to find Sin A, Cos A, and Tan A.

Let us calculate Sin A first,

Sin A = Opposite / Hypotenuse

=> Sin A = BC / AC

=> Sin A = 15 / 17

Cos A = Adjacent / Hypotenuse

=> Cos A = AB / AC

=> Cos A = 8 / 17

Tan A = Opposite / Adjacent

=> Tan A = BC / AB

=> Tan A = 15 / 8