To divide a line segment AB in the ratio 3:7, first a ray AX is drawn

This question was asked in Construction 11.1

To divide a line segment AB in the ratio 3:7, first a ray AX is drawn so that angle BAX is an acute
angle and then at equal distances point are marked on the ray AX such that the minimum,
number of these point is
(A) 3 (B)10 (C)7 (D)12