What is the sum of the digits of least number which, when divided by 6, 7 and 9 leaves remainder 4 in each case but, exactly divisible by 11.
Answers!
Firstly, find the LCM of 6 , 7 and 9
LCM = 126
Let the number be x.
Then, x will be the form of 126q 4
X= 126q 4
x= 126 × 8 4
x= 1012
Which gives remainder 4 in each case and also divisible by 11.
So, sum of the digits of the number is 4.
Comment
Answer the question...
Firstly, find the LCM of 6 , 7 and 9
LCM = 126
Let the number be x.
Then, x will be the form of 126q 4
X= 126q 4
x= 126 × 8 4
x= 1012
Which gives remainder 4 in each case and also divisible by 11.
So, sum of the digits of the number is 4.
LCM = 126
Let the number be x.
Then, x will be the form of 126q 4
X= 126q 4
x= 126 × 8 4
x= 1012
Which gives remainder 4 in each case and also divisible by 11.
So, sum of the digits of the number is 4.
Comment