Differentiate x^sinx, x>0 w.r.t. x.
Answers!
y=x^sinx
log y= log x^sinx
log y= sinx logx
1/y(dy/dx) = cosx logx + (sinx)/x
dy/dx= y[cosx logx = 1]
dy/dx = x^sinx (cosx log x + 1)
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Answer the question...
y=x^sinx
log y= log x^sinx
log y= sinx logx
1/y(dy/dx) = cosx logx + (sinx)/x
dy/dx= y[cosx logx = 1]
dy/dx = x^sinx (cosx log x + 1)
Comment