asinθ- bcosθ = c and asinθ+ bcosθ = √a≤ + b≤ - c≤ prove that cosθ =sinθor a≤ = b≤

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vijay89
Feb. 24, 2017, 7 p.m.

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Davneet Singh
Feb. 24, 2017, 7:16 p.m.

Hi Vijay

Converse of basic proportionality theorem is Theorem 6.2, please check https://www.teachoo.com/4285/1051/Theorem-6.2---Converse-of-Basic-Proportionality-Theorem-/category/Theorems/

 

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vijay89
Feb. 24, 2017, 7:05 p.m.

 prove that tanθ/1+cotθ + cotθ/1+tanθ = 1 + secθcosecθ

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vijay89
Feb. 24, 2017, 7:01 p.m.

Converse of basic proportionality theorem by easy method 

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