Answers!
Hello
First n natural numbers are
1, 2, 3, 4, 5, 6, .... n
Sum of first n natural numbers = n/2 (a + l)
where a = first term = 1
l = last term = n
Thus,
Sum of first n natural numbers = n/2 (1 + n) = n (n + 1)/2
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Answer the question...
Hello
First n natural numbers are
1, 2, 3, 4, 5, 6, .... n
Sum of first n natural numbers = n/2 (a + l)
where a = first term = 1
l = last term = n
Thus,
Sum of first n natural numbers = n/2 (1 + n) = n (n + 1)/2
Comment