Hello
First n natural numbers are
1, 2, 3, 4, 5, 6, .... n
Sum of first n natural numbers = n/2 (a + l)
where a = first term = 1
l = last term = n
Thus,
Sum of first n natural numbers = n/2 (1 + n) = n (n + 1)/2
Written on Dec. 20, 2017, 10:51 a.m.