1. Chapter 8 Class 11 Sequences and Series
  2. Serial order wise
  3. Arithmetic Progression
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Question 14 - Arithmetic Progression - Chapter 8 Class 11 Sequences and Series

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Ex9.2,14 Insert five numbers between 8 and 26 such that the resulting sequence is an A.P. We know that to insert n numbers between a & b common difference (d) = ( )/( + 1) Here, We need to insert 5 numbers between 8 and 26 So, b = 26 , a = 8 & number of terms to be inserted = n = 5 Therefore, d = (26 8)/(5 + 1) = 18/6 = 3 Now, a = 8, d = 3 & b = 26 Hence five numbers between 8 and 26 are 11, 14, 17, 20 & 23

  1. Chapter 8 Class 11 Sequences and Series
  2. Serial order wise

    3. Arithmetic Progression

    Sum of Series →
Sum of Series →
Chapter 8 Class 11 Sequences and Series
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo