Check sibling questions


Transcript

Question 3 Write the general term in the expansion of (x2 – y)6 We know that General term of expansion (a + b)n is Tr + 1 = nCr an–r br For (x2 – y)6 Putting n = 6 , a = x2 , b = –y Tr + 1 = 6Cr (x2)6 – r (–y)r = 6!/𝑟!(6 − 𝑟)! . (x)2(6 – r) . (–1)r . (y)r = (–1)r 𝟔!/𝒓!(𝟔 − 𝒓)! . x12 – 2r . yr

  1. Chapter 7 Class 11 Binomial Theorem
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo