1. Chapter 8 Class 10 Introduction to Trignometry
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  3. Ex 8.1
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Ex 8.1, 9 - Chapter 8 Class 10 Introduction to Trignometry

Last updated at Dec. 13, 2024 by Teachoo

Transcript

Ex 8.1, 9 In triangle ABC, right-angled at B, if tan A = 1/√3, find the value of sin A cos C + cos A sin C Given tan A = 1/√3 (π‘Ίπ’Šπ’…π’† π’π’‘π’‘π’π’”π’Šπ’•π’† 𝒕𝒐 𝑨)/(π‘Ίπ’Šπ’…π’† 𝒂𝒅𝒋𝒂𝒄𝒆𝒏𝒕 𝒕𝒐 𝑨) = 𝟏/βˆšπŸ‘ 𝐡𝐢/𝐴𝐡 = 1/√3 Let BC = x & AB = βˆšπŸ‘ x We have to find sin A cos C + cos A sin C Putting sin A = 1/2 , cos A = √3/2 , sin C = √3/2 & cos C = 1/2 = (𝟏/𝟐)Γ—(𝟏/𝟐)+(βˆšπŸ‘/𝟐)Γ—(βˆšπŸ‘/𝟐) = 1/4 + (√3 Γ— √3)/4 = 1/4 + 3/4 = (1 + 3)/4 = 4/4 = 1 So, sin A cos C + cos A sin C = 1 Ex 8.1, 9 In triangle ABC, right-angled at B, if tan A = 1/√3, find the value of (ii) cos A cos C – sin A sin C cos A cos C – sin A sin C Putting sin A = 1/2 , cos A = √3/2 , sin C = √3/2 & cos C = 1/2 = (βˆšπŸ‘/𝟐)Γ—πŸ/πŸβˆ’(𝟏/𝟐)Γ—(βˆšπŸ‘/𝟐) = (√3/4)βˆ’(√3/4) = 0 Hence, cos A cos C – sin A sin C = 0
  1. Chapter 8 Class 10 Introduction to Trignometry
  2. Serial order wise

    3. Ex 8.1

    Ex 8.2 →
Ex 8.2 →
Chapter 8 Class 10 Introduction to Trignometry
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo