Ex 2.3, 1 (iv) - Chapter 2 Class 9 Polynomials
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 2.3, 1 Determine which of the following polynomials has (x + 1) a factor: (iv) x3 x2 (2 + 2) x + 2 Finding remainder when x3 x2 (2 + 2) x + 2 is divided by x + 1 Step 1: Put Divisor = 0 x + 1 = 0 x = 1 Step 2: Let p(x) = x3 x2 (2 + 2) x + 2 Putting x = 1 p( 1) = ( 1)3 ( 1)2 (2 + 2) ( 1) + 2 = 1 (1) + (2 + 2) + 2 = 1 1 + 2 + 2 + 2 = 2 + 2 + 2 + 2 = 2 2 Thus, Remainder = p( 1) = 2 2 Since remainder is not zero, x + 1 is not a factor of x3 x2 (2 + 2) x + 2
Ex 2.3
Ex 2.3, 1 (ii)
Ex 2.3, 1 (iii)
Ex 2.3, 1 (iv) Important You are here
Ex 2.3, 2 (i)
Ex 2.3, 2 (ii) Important
Ex 2.3, 2 (iii)
Ex 2.3, 3 (i)
Ex 2.3, 3 (ii) Important
Ex 2.3, 3 (iii) Important
Ex 2.3, 3 (iv)
Ex 2.3, 4 (i)
Ex 2.3, 4 (ii) Important
Ex 2.3, 4 (iii)
Ex 2.3, 4 (iv) Important
Ex 2.3, 5 (i)
Ex 2.3, 5 (ii) Important
Ex 2.3, 5 (iii) Important
Ex 2.3, 5 (iv)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo