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For what value of k, the pair of linear equations 3x + y = 3 and  6x + ky = 8 does not have a solution.


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Question 3 For what value of k, the pair of linear equations 3x + y = 3 and 6x + ky = 8 does not have a solution.3x + y − 3 = 0 Comparing with a1x + b1y + c1 = 0 ∴ a1 = 3 , b1 = 1 , c1 = −3 6x + ky − 8 = 0 Comparing with a2x + b2y + c2 = 0 ∴ a2 = 6 , b2 = k, c2 = −8 Therefore, a1 = 3 , b1 = 1 , c1 = −3 & a2 = 6 , b2 = k, c2 = −8 𝒂𝟏/𝒂𝟐 𝑎1/𝑎2 = 3/6 𝑎1/𝑎2 = 1/2 𝒃𝟏/𝒃𝟐 𝑏1/𝑏2 = 1/𝑘 𝒄𝟏/𝒄𝟐 𝑐1/𝑐2 = (−3)/(−8) 𝑐1/𝑐2 = 3/8 Since the equations don’t have a solution 𝑎1/𝑎2 = 𝑏1/𝑏2 ≠ 𝑐1/𝑐2 1/2=1/𝑘≠3/8 Thus, 1/2=1/𝑘 k = 2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo