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Ex 9.3, 1 - Carry out the multiplication of expressions in each pairs

Ex 9.3, 1 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2
Ex 9.3, 1 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3 Ex 9.3, 1 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 4 Ex 9.3, 1 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 5

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Ex 8.3, 1 Carry out the multiplication of the expressions in each of the following pairs. (i) 4𝑝, π‘ž + π‘Ÿ 4𝑝×(π‘ž+π‘Ÿ) = (4π‘Γ—π‘ž)+(4π‘Γ—π‘Ÿ) = πŸ’π’‘π’’+𝒑𝒓 Ex 8.3, 1 Carry out the multiplication of the expressions in each of the following pairs. (ii) π‘Žπ‘, π‘Žβˆ’π‘ π‘Žπ‘Γ—(π‘Žβˆ’π‘) = (π‘Žπ‘Γ—π‘Ž)βˆ’(π‘Žπ‘Γ—π‘) = (π‘ŽΓ—π‘Ž)π‘βˆ’π‘Ž(𝑏×𝑏) = 𝒂^𝟐 π’ƒβˆ’π’‚π’ƒ^𝟐 Ex 8.3, 1 Carry out the multiplication of the expressions in each of the following pairs. (iii) π‘Ž + 𝑏, 7π‘Ž^2 𝑏^2 (π‘Ž+𝑏)Γ—7π‘Ž^2 𝑏^2 = (π‘ŽΓ—7π‘Ž^2 𝑏^2 )+(𝑏×7π‘Ž^2 𝑏^2 ) = 7π‘Ž^3 𝑏^2+7π‘Ž^2 𝑏^3 Ex 8.3, 1 Carry out the multiplication of the expressions in each of the following pairs. (iv) π‘Ž^2βˆ’ 9, 4π‘Ž (π‘Ž^2βˆ’ 9)Γ—4π‘Ž = (π‘Ž^2Γ—4π‘Ž)βˆ’(9Γ—4π‘Ž) = πŸ’π’‚^πŸ‘βˆ’πŸ‘πŸ”π’‚ Ex 8.3, 1 Carry out the multiplication of the expressions in each of the following pairs. (v) π‘π‘ž+π‘žπ‘Ÿ+π‘Ÿπ‘, 0 (π‘π‘ž+π‘žπ‘Ÿ+π‘Ÿπ‘)Γ—0 = (π‘π‘žΓ—0)+(π‘žπ‘ŸΓ—0)+(π‘Ÿπ‘Γ—0) = 0+0+0 = 0

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.