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  1. Chapter 13 Class 7 Exponents and Powers
  2. Serial order wise

Transcript

Ex 13.1, 8 (Method 1) Compare the following numbers: (i) 2.7 × 1012 ; 1.5 × 108 2.7 × 1012 = 27/10 × 1000000000000 = 27 × 100000000000 = 2700000000000 1.5 × 108 = 15/10 × 100000000 = 15 × 10000000 = 150000000 Since 2.7 × 1012 has more digits It is greater So, 2.7 × 1012 > 1.5 × 108 Ex 13.1, 8 (Method 2) Compare the following numbers: (i) 2.7 × 1012 ; 1.5 × 108 2.7 × 1012 ⎕ 1.5 × 108 Comparing powers of 10 1012 > 108 ∴ 2.7 × 1012 > 1.5 × 108 Ex 13.1, 8 Compare the following numbers: (ii) 4 × 1014 ; 3 × 1017 4 × 1014 ⎕ 3 × 1017 Comparing powers of 10 1014 < 1017 ∴ 4 × 1014 < 3 × 1017

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.