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Example 9 - Chapter 9 Class 7 Perimeter and Area
Last updated at December 16, 2024 by Teachoo
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
- Area of parallelogram
- Area of triangle
-
Circumference of circle
- Perimeter of a combination of shapes
- Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Example 9 The radius of a circular pipe is 10 cm. What length of a tape is required to wrap once around the pipe (Ļ = 3.14)?Here, Length of tape required = Circumference of pipe Radius of pipe = r = 10 cm Circumference of pipe = 2šr = 2 Ć 3.14 Ć 10 = 2 Ć 314/100 Ć 10 = 2 Ć 314/10 = 628/10 = 62.8 cm ā“ Length of tape required = 62.8 cm Hence, 62.8 cm of tape is required to wrap once around the pipe
