Ex 11.1, 6 - A wire is in the shape of a rectangle. Its length is 40

Ex 11.1, 6 - Chapter 11 Class 7 Perimeter and Area - Part 2
Ex 11.1, 6 - Chapter 11 Class 7 Perimeter and Area - Part 3
Ex 11.1, 6 - Chapter 11 Class 7 Perimeter and Area - Part 4

Go Ad-free

Transcript

Question 6 A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area? We convert rectangular wire to square So, length of wire will be the same ∴ Perimeter of rectangle = Perimeter of square Rectangle Length of rectangle = l = 40 cm Breadth of rectangle = b = 22 cm Perimeter = 2 (l + b) = 2 (40 + 22) = 124 cm Square Let side = a Perimeter = 4a Now, Perimeter of rectangle = Perimeter of square 124 = 4a 124/4 = a 31 = a a = 31 cm So, Side of square is 31 cm Now, We need to find whose area is bigger Finding area Rectangle Area = l × b = 40 × 22 = 88 cm2 Square Area = a × a = 31 × 31 = 961 cm2 So, Area of square is greater then area of rectangle

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.