Question 3 - Bisector of an angle - Practical Geometry

Last updated at April 16, 2024 by

Here, we will draw right angle i.e. 90° using protractor.

To draw 90° using compass, please check Ex 11.1, 1 of Class 9 NCERT

Ex 14.6, 3 - Draw a right angle and construct its bisector

Ex 14.6, 3 - Chapter 14 Class 6 Practical Geometry - Part 2
Ex 14.6, 3 - Chapter 14 Class 6 Practical Geometry - Part 3
Ex 14.6, 3 - Chapter 14 Class 6 Practical Geometry - Part 4
Ex 14.6, 3 - Chapter 14 Class 6 Practical Geometry - Part 5

Transcript

Question 3 Draw a right angle and construct its bisector Here, we will draw right angle i.e. 90° using protractor. To draw 90° using compass, please check Ex 11.1, 1 of Class 9 NCERT We follow these steps Draw a ray OA 2. Place center of protractor on point O, and coincide line OA and Protractor line Mark point B on 90° Join OB ∴ ∠ AOB = 90° Now, we need to find its bisector. We follow these steps 1. Mark points C and D where arc intersects OA and OB 2. Now, taking C and D as centers and with the radius more than 1/2 CD, draw arcs to intersect each other. 3. Let them intersect at point E 4. Join O & E ∴ OE is the bisector of ∠ BOA = 90°

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.