# Ex 14.4, 3 - Chapter 14 Class 6 Practical Geometry

Last updated at Sept. 28, 2018 by Teachoo

Last updated at Sept. 28, 2018 by Teachoo

Transcript

Ex 14.4, 3 Draw a line l and a point X on it. Through X, draw a line segment (ππ) Μ perpendicular to l. Now draw a perpendicular to (ππ) Μ at Y. (use ruler and compasses) Letβs follow these steps 1. Given a line l with point X marked on it Letβs follow these steps 1. Given a line l with point X marked on it 3. Now with A as center, and radius more than AX, draw an arc. With B as center, and same radius as before, draw an arc 4. Mark the point of intersection of the two arcs as point Y Join X & Y. β΄ XY is perpendicular to line l Now, We need to draw line perpendicular to XY at Y So, we need to draw perpendicular on a point on it Letβs follow these steps 1. With Y as center, and any radius, draw an arc intersecting XY at points P and Q Now with P as center, and radius more than PY, draw an arc. With Q as center, and same radius as before, draw an arc 3. Mark the point of intersection of the two arcs as point Z Join Z & Y. β΄ ZY is the line perpendicular to XY at Y

Chapter 14 Class 6 Practical Geometry

Concept wise

- Basics
- Construction of a circle when its radius is known
- Construction of a line segment of a given length
- Constructing a copy of a given line segment
- Perpendicular to a line through a point on it
- Perpendicular to a line through a point not on it
- Perpendicular bisector of a line segment
- Constructing an angle using protractor
- Bisector of an angle
- Constructing angles using compass
- Constructing a copy of a given angle

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.