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Last updated at Sept. 28, 2018 by Teachoo

Transcript

Ex 14.4, 2 Draw any line segment (ππ) Μ . Take any point R not on it. Through R, draw a perpendicular to (ππ) Μ . (Use ruler and set-square) Letβs take an example 1. Given a line segment PQ with point R not on it Place set square on the line so that line is exactly above the set square 3. Put ruler on the hypotenuse line of the set square 4. Keeping the ruler in the same position, slide the set-square till one end of the set-square passes through point P 4. Keeping the ruler in the same position, slide the set-square till one end of the set-square passes through point P 5. Draw a line along the edge of the set square, keeping set-square firm Let the line intersect line l at S Thus, RS is the perpendicular to PQ

Chapter 14 Class 6 Practical Geometry

Concept wise

- Basics
- Construction of a circle when its radius is known
- Construction of a line segment of a given length
- Constructing a copy of a given line segment
- Perpendicular to a line through a point on it
- Perpendicular to a line through a point not on it
- Perpendicular bisector of a line segment
- Constructing an angle using protractor
- Bisector of an angle
- Constructing angles using compass
- Constructing a copy of a given angle

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.