Ex 14.2, 5 - Given AB of length 7.3 cm and CD of length 3.4 cm

Ex 14.2, 5 - Chapter 14 Class 6 Practical Geometry - Part 2
Ex 14.2, 5 - Chapter 14 Class 6 Practical Geometry - Part 3
Ex 14.2, 5 - Chapter 14 Class 6 Practical Geometry - Part 4
Ex 14.2, 5 - Chapter 14 Class 6 Practical Geometry - Part 5


Transcript

Question 5 Given (𝐴𝐡) Μ… of length 7.3 cm and (𝐢𝐷) Μ… of length 3.4 cm, construct a line segment (π‘‹π‘Œ) Μ… such that the length of (π‘‹π‘Œ) Μ… is equal to the difference between the lengths of (𝐴𝐡) Μ… and (𝐢𝐷) Μ… . Verify by measurement. Given (𝐴𝐡) Μ… = 7.3 cm (𝐢𝐷) Μ… = 3.4 cm We need to make line segment (π‘‹π‘Œ) Μ… such that XY = AB – CD Let’s see how we do it Let’s follow these steps 1. Draw a line l mark point X on it 2. Measure (𝐴𝐡) Μ… = 7.3 cm using compass 3. Now keeping compass opened the same length. We keep pointed end at point X, and draw an arc on line l So, (𝑋𝐡′) Μ… = (𝐴𝐡) Μ… = 7.3 cm. 4. Measure (𝐢𝐷) Μ… = 3.4 cm using compass 5. Now keeping compass opened the same length. We keep pointed end at point B’, and draw an arc on line l So, (π‘Œπ΅β€²) Μ… = (𝐢𝐷) Μ… = 3.4 cm. Thus, required line segment (π‘‹π‘Œ) Μ… = 3.9 cm

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.