Example 5 - In Fig 7.23, AB = AC and AD is the bisector of BAC

Example 5 - Chapter 7 Class 7 Congruence of Triangles - Part 2
Example 5 - Chapter 7 Class 7 Congruence of Triangles - Part 3

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Example 5 In Fig 7.23,AB = AC and AD is the bisector of ∠BAC. (i) State three pairs of equal parts in triangles ADB and ADC. In ∆ADB and ∆ADC, AB = AC ∠BAD = ∠CAD AD = AD Example 5 In Fig 7.23,AB = AC and AD is the bisector of ∠BAC. (ii) Is ∆ADB ≅ ∆ADC? Give reasons.In ∆ADB and ∆ADC, AB = AC ∠BAD = ∠CAD AD = AD ∴ ∆ADB ≅ ∆ADC Example 5 In Fig 7.23,AB = AC and AD is the bisector of ∠BAC. (iii) Is ∠B = ∠C? Give reasons.Since ∆ADB ≅ ∆ADC By CPCT ∠B = ∠C

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.