Example 5 - In Fig 7.23, AB = AC and AD is the bisector of BAC

Example 5 - Chapter 7 Class 7 Congruence of Triangles - Part 2
Example 5 - Chapter 7 Class 7 Congruence of Triangles - Part 3

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Example 5 In Fig 7.23,AB = AC and AD is the bisector of ∠BAC. (i) State three pairs of equal parts in triangles ADB and ADC. In ∆ADB and ∆ADC, AB = AC ∠BAD = ∠CAD AD = AD Example 5 In Fig 7.23,AB = AC and AD is the bisector of ∠BAC. (ii) Is ∆ADB ≅ ∆ADC? Give reasons.In ∆ADB and ∆ADC, AB = AC ∠BAD = ∠CAD AD = AD ∴ ∆ADB ≅ ∆ADC Example 5 In Fig 7.23,AB = AC and AD is the bisector of ∠BAC. (iii) Is ∠B = ∠C? Give reasons.Since ∆ADB ≅ ∆ADC By CPCT ∠B = ∠C

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