Let’s do this by examples
Find supplementary angle of 100°
Given angle = 100°
We know that,
If two angles are supplementary, their sum is 180°
So,
Angle 1 + Angle 2 = 180°
100° + Angle 2 = 180°
Angle 2 = 180° − 100°
Angle 2 = 80°
So, supplementary of 100° is 80°
Find supplementary angle of 90°
Given angle = 90°
We know that,
If two angles are supplementary, their sum is 180°
So,
Angle 1 + Angle 2 = 180°
90° + Angle 2 = 180°
Angle 2 = 180° − 90°
Angle 2 = 90°
So, supplementary of 90° is 90°
Find supplementary angle of 55°
Given angle = 55°
We know that,
If two angles are supplementary, their sum is 180°
So,
Angle 1 + Angle 2 = 180°
55° + Angle 2 = 180°
Angle 2 = 180° − 55°
Angle 2 = 125°
So, supplementary of 55° is 125°
Find supplementary angle of 125°
Given angle = 125°
We know that,
If two angles are supplementary, their sum is 180°
So,
Angle 1 + Angle 2 = 180°
125° + Angle 2 = 180°
Angle 2 = 180° − 125°
Angle 2 = 55°
So, supplementary of 125° is 55°
Among two supplementary angles, the measure of the larger angle is 44° more than the measure of the smaller. Find their measure .
Let larger angle be ∠1
and smaller angle be ∠2.
Given,
∠1 = ∠2 + 44°
We know that,
If two angles are supplementary, their sum is of 180°
∴∠1 + ∠2 = 180°
(∠2 + 44°) + ∠2 = 180°
∠2 + 44° + ∠2 = 180°
∠2 + ∠2 = 180° − 44°
2 × ∠2 = 136°
∠2 = (136°)/2
∠2 = 68°
Now,
∠1 = ∠2 + 44°
∠1 = 68° + 44°
∠1 = 112°
So, Required angles are of 112° and 68 °
