###
**
Finding
**
**
supplementary
**
**
angles
**

Let’s do this by examples

###
**
Find supplementary angle of 100°
**

Given angle = 100°

We know that,

If two angles are supplementary, their sum is 180°

So,

Angle 1 + Angle 2 = 180°

100° + Angle 2 = 180°

Angle 2 = 180° − 100°

Angle 2 = 80°

So, supplementary of 100° is
**
80°
**

###
**
Find supplementary angle of 90°
**

Given angle = 90°

We know that,

If two angles are supplementary, their sum is 180°

So,

Angle 1 + Angle 2 = 180°

90° + Angle 2 = 180°

Angle 2 = 180° − 90°

Angle 2 = 90°

So, supplementary of 90° is
**
90°
**

###
**
Find supplementary angle of 55°
**

Given angle = 55°

We know that,

If two angles are supplementary, their sum is 180°

So,

Angle 1 + Angle 2 = 180°

55° + Angle 2 = 180°

Angle 2 = 180° − 55°

Angle 2 = 125°

So, supplementary of 55° is
**
125°
**

###
**
Find supplementary angle of 125°
**

Given angle = 125°

We know that,

If two angles are supplementary, their sum is 180°

So,

Angle 1 + Angle 2 = 180°

125° + Angle 2 = 180°

Angle 2 = 180° − 125°

Angle 2 = 55°

So, supplementary of 125° is
**
55°
**

###
**
Among two supplementary angles, the measure of the larger angle is 44° more than the measure of the smaller. Find their measure .
**

Let larger angle be ∠1

and smaller angle be ∠2.

Given,

∠1 = ∠2 + 44°

We know that,

If two angles are supplementary, their sum is of 180°

∴∠1 + ∠2 = 180°

(∠2 + 44°) + ∠2 = 180°

∠2 + 44° + ∠2 = 180°

∠2 + ∠2 = 180° − 44°

2 × ∠2 = 136°

∠2 = (136°)/2

∠2 = 68°

Now,

∠1 = ∠2 + 44°

∠1 = 68° + 44°

∠1 = 112°

So, Required angles are of
**
112° and 68
**
°