Let’s do this by examples

 

Find supplementary angle of 100°

 

Given angle  = 100°

 

We know that,

  If two angles are supplementary, their sum is 180°

 

So,

Angle 1 + Angle 2 = 180°

100° + Angle 2 = 180°

Angle 2 = 180° − 100°

Angle 2 = 80°

 

So, supplementary of 100° is 80°       

 

Find supplementary angle of 90°

Given angle  = 90°

 

We know that,

  If two angles are supplementary, their sum is 180°

 

So,

Angle 1 + Angle 2 = 180°

90° + Angle 2 = 180°

Angle 2 = 180° − 90°

Angle 2 = 90°

 

So, supplementary of 90° is 90°      

 

Find supplementary angle of 55°

Given angle  = 55°

 

We know that,

  If two angles are supplementary, their sum is 180°

 

So,

Angle 1 + Angle 2 = 180°

55° + Angle 2 = 180°

Angle 2 = 180° − 55°

Angle 2 = 125°

 

So, supplementary of 55° is 125°      

 

Find supplementary angle of 125°

Given angle  = 125°

 

We know that,

  If two angles are supplementary, their sum is 180°

 

So,

Angle 1 + Angle 2 = 180°

    125° + Angle 2 = 180°

               Angle 2 = 180° − 125°

       Angle 2 = 55°

 

So, supplementary of 125° is 55°      

 

Among two supplementary angles, the measure of the larger angle is 44° more than the measure of the smaller. Find their measure .

 

Let larger angle be ∠1

and smaller angle be ∠2.  

 

Given,

   ∠1 = ∠2 + 44°

 

We know that,

If two angles are supplementary, their sum is of 180°

 

∴∠1 + ∠2 = 180°  

 (∠2 + 44°) + ∠2 = 180°

 

∠2 + 44° + ∠2 = 180°

∠2 + ∠2 = 180° − 44°

  2 × ∠2 = 136°

 ∠2 = (136°)/2

 ∠2 = 68°

 

Now,

  ∠1 = ∠2 + 44°  

  ∠1 = 68° + 44°

  ∠1 = 112°

So, Required angles are of 112° and 68 °  

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.