Let’s take a example

 

Find complementary angle of 45°

Given angle  = 45°

 

We know that,

 

  If two angles are complementary, their sum is 90°

 

So,

Angle 1 + Angle 2 = 90°

45° + Angle 2 = 90°

 

         Angle 2 = 90° − 45°

         Angle 2 = 45°

So, complementary of 45° is 45°      

 

 

Find complementary angle of 65°

Given angle  = 65°

 

We know that,

  If two angles are complementary, their sum is 90°

 

So,

Angle 1 + Angle 2 = 90°

65° + Angle 2 = 90°

        Angle 2 = 90° − 65°

       Angle 2 = 25°

 

So, complementary of 65° is 25°      

 

Find complementary angle of 41°

Given angle  = 41°

 

We know that,

 

  If two angles are complementary, their sum is 90°

So,

Angle 1 + Angle 2 = 90°

41° + Angle 2 = 90°

        Angle 2 = 90° − 41°

        Angle 2 = 49°

 

So, complementary of 41° is 49°      

 

Find complementary angle of 54°

Given angle  = 54°

 

We know that,

  If two angles are complementary, their sum is 90°

So,

Angle 1 + Angle 2 = 90°

54° + Angle 2 = 90°

Angle 2 = 90° − 54°

Angle 2 = 36°

 

So, complementary of 54° is 36°      

 

The difference in the measures of two complementary angles is 12 °. Find the measures of the angles.

 

Let’s assume one angle be ∠1

and the other to be ∠2.  

Where ∠1 > ∠2

 

Now,

   ∠1 − ∠2 = 12°

   ∠1 = ∠2 + 12°

 

We know that,

  If two angles are complimentary, their sum is 90°

 

So,

  ∠1 + ∠2 = 90°

  (∠2 + 12°) + ∠2 = 90°

  ∠2 + 12° + ∠2 = 90°

  2∠2 = 90° − 12°

  2∠2 = 78°

 ∠2 = (78°)/2

 ∠2 = 39°

 

Now,

 ∠1 = ∠2 + 12°   

 ∠1 = 39° + 12°

 ∠1 = 51°

 

So, Required angles are of 51°  and 39°   

    

   

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.