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In a regular polygon

  • All sides are equal
  • All angles are equal
  •  

Let

∠ A = ∠ B = ∠ C = ∠ D = ∠ E = ∠ F = x

 

We know that

  Sum of angles of a regular hexagon = (n – 2)  × 180°

      Putting n = 6

                 = (6 – 2) × 180°

              = 4 × 180°

            = 720°

 

Now,

  Sum of angles of a regular hexagon= 720°

  ∠ A + ∠ B + ∠ C + ∠ D + ∠ E + ∠ F = 720°

  x + x + x + x + x + x = 720°

  6x = 720°

  x = (720°)/6

  x = 120°

Thus,

  Interior Angle of a Regular Hexagon = 120°

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In general

  Interior Angle of a Polygon × Number of sides = Sum of angles

  Interior Angle of a Regular Polygon  × n = (n – 2) × 180°

  Interior Angle of a Regular Polygon  = ((n - 2))/n   × 180°

 

 

  1. Chapter 3 Class 8 Understanding Quadrilaterals
  2. Concept wise
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.