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Example 3 - Chapter 6 Class 8 Squares and Square Roots
Last updated at March 23, 2023 by Teachoo
Transcript
Example 3 Find a Pythagorean triplet in which one member is 12. We know 2m, π^2β1 and π^2+1 form a Pythagorean triplet. Given, One member of the triplet = 12. Let 2m = 12 2m = 12 m = 12/2 m = 6 Let π^πβπ" = 12" π^2 = 12 + 1 π^2 = 13 Since, 13 is not a square number, β΄ π^2β1 β 12 It is not possible. Let π^π+π = 12 π^2 = 12 β 1 π^2 = 11 Since, 11 is not a square number, β΄ π^2+1 β 12 It is not possible. Therefore, m = 6 Finding Triplets for m = 6 1st number = 2m 2nd number = π^2β1 3rd number = π^2+1 β΄ The required triplet is 12, 35, 37
