

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Last updated at May 29, 2023 by Teachoo
Example 2 Write a Pythagorean triplet whose smallest member is 8. We know 2m, π^2β1 and π^2+1 form a Pythagorean triplet. We know 2m, π^πβπ and π^π+π form a Pythagorean triplet. Given, Smallest member of the triplet = 8. Let 2m = 8 2m = 8 m = 8/2 m = 4 Let π^πβπ" = 8" π^2 = 8 + 1 π^2 = 9 β΄ m = 3 Let π^π+π = 8 π^2 = 8 β 1 π^2 = 7 Since, 7 is not a square number, β΄ π^2+1 β 8 It is not possible. Therefore, m = 4 or m = 3 Finding Triplets for m = 3 1st number = 2m 2nd number = π^2β1 3rd number = π^2+1 β΄ The required triplet is 6, 8, 10 But 8 is not a smallest member of this triplet. So, lets try for m = 4 Finding Triplets for m = 4 1st number = 2m 2nd number = π^2β1 3rd number = π^2+1 As 8 is the smallest member of this triplet. β΄ The required triplet is 8, 15, 17