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  1. Chapter 5 Class 8 Data Handling
  2. Serial order wise
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Ex 5.3, 4 Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of . (i) getting a number 6? Total number of slips = 10 Number of Slips with 6 written on them = 1 Probability = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘™๐‘–๐‘๐‘  ๐‘ค๐‘–๐‘กโ„Ž 6 ๐‘ค๐‘Ÿ๐‘–๐‘ก๐‘ก๐‘’๐‘› ๐‘œ๐‘› ๐‘กโ„Ž๐‘’๐‘š)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘™๐‘–๐‘๐‘ ) = ๐Ÿ/๐Ÿ๐ŸŽ Ex 5.3, 4 (ii) getting a number less than 6? Slips with a number less than 6 = 1, 2, 3, 4, 5, 6 Number of slips with a number less than 6 = 5 Probability = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘™๐‘–๐‘๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘Ž ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘™๐‘’๐‘ ๐‘  ๐‘กโ„Ž๐‘Ž๐‘› 6)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘™๐‘–๐‘๐‘ ) = 5/10 = ๐Ÿ/๐Ÿ Ex 5.3, 4 (iii) getting a number greater than 6? Slip with a number greater than 6 = 7, 8, 9, 10 Number of slips greater than 6 written on them = 4 Probability = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘™๐‘–๐‘๐‘  ๐‘”๐‘Ÿ๐‘’๐‘Ž๐‘ก๐‘’๐‘Ÿ ๐‘กโ„Ž๐‘Ž๐‘› 6 )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘™๐‘–๐‘๐‘ ) = 4/10 = ๐Ÿ/๐Ÿ“ Ex 5.3, 4 (iv) getting a 1-digit number? One digit number = 1, 2, 3, 4, 5, 6, 7, 8, 9 โˆด Number of slips with one-digit number= 9 Probability = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘™๐‘–๐‘๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘œ๐‘›๐‘’ ๐‘‘๐‘–๐‘”๐‘–๐‘ก ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘™๐‘–๐‘๐‘ ) = 9/10

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.