# Ex 4.2, 4 - Chapter 4 Class 7 Simple Equations

Last updated at July 5, 2018 by Teachoo

Last updated at July 5, 2018 by Teachoo

Transcript

Ex 4.2, 4Solve the following equations: (a) 10p = 10010p = 100 Dividing 10 both sides 10๐/10 = 100/10 p = 10 Ex 4.2, 4Solve the following equations: (b) 10p + 10 = 100 10p + 10 = 100 Subtracting both sides by 10 10p + 10 โ 10 = 100 โ 10 10p = 90 Dividing both sides by 10 10๐/10 = 90/10 p = 9 Ex 4.2, 4Solve the following equations: (c) ๐/4 = 5๐/4 = 5 Multiply both sides by 4 ๐/4 ร 4 = 5 ร 4 p = 20 Ex 4.2, 4Solve the following equations: (d) (โ๐)/3 = 5(โ๐)/3 = 5 Multiplying both sides by 3 (โ๐)/3 ร 3 = 5 ร 3 โp ร 1 = 15 โp = 15 Multiplying both sides by โ1 โp ร โ1 = 15 ร โ1 p = โ15 Ex 4.2, 4Solve the following equations: (e) 3๐/4 = 63๐/4 = 6 Multiplying both sides by 4 3๐/4 ร 4 = 6 ร 4 3p = 24 Diving both sides by 3 3๐/3 = 24/3 p = 8 Ex 4.2, 4Solve the following equations: (f) 3s = โ9 Ex 4.2, 4Solve the following equations: (g) 3s + 12 = 0 3s + 12 = 0 Subtracting both sides by 12 3s + 12 โ 12 = 0 ร 12 3s = โ12 Diving both sides by 3 3๐ /3 = (โ12)/3 s = โ4 Ex 4.2, 4Solve the following equations: (h) 3s = 03s = 0 Diving both sides by 3 3๐ /3 = 0/3 s = 0 Ex 4.2, 4Solve the following equations: (i) 2q = 62q = 6 Diving both sides by 2 2๐/2 = 6/2 q = 3 Ex 4.2, 4Solve the following equations: (j) 2q โ 6 = 02q โ 6 = 0 Adding 6 to both sides 2q โ 6 + 6 = 0 + 6 2q = 6 Diving both sides by 2 2๐/2 = 6/2 q = 3 Ex 4.2, 4Solve the following equations: (k) 2q + 6 = 02q + 6 = 0 Subtracting both sides by 6 2q + 6 โ 6 = 0 โ 6 2q = โ6 Diving both sides by 2 2๐/2 = (โ6)/2 q = โ3 Ex 4.2, 4Solve the following equations: (l) 2q + 6 = 122q + 6 = 12 Subtracting both sides by 6 2q + 6 โ 6 = 12 โ 6 2q = 6 Diving both sides by 2 2๐/2 = 6/2 q = 3

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.