Slide21.JPG

Slide22.JPG
Slide23.JPG Slide24.JPG Slide25.JPG Slide26.JPG Slide27.JPG Slide28.JPG Slide29.JPG Slide30.JPG Slide31.JPG Slide32.JPG

  1. Chapter 4 Class 7 Simple Equations
  2. Serial order wise
Ask Download

Transcript

Ex 4.2, 4 Solve the following equations: (a) 10p = 10010p = 100 Dividing 10 both sides 10๐‘/10 = 100/10 p = 10 Ex 4.2, 4 Solve the following equations: (b) 10p + 10 = 100 10p + 10 = 100 Subtracting both sides by 10 10p + 10 โˆ’ 10 = 100 โˆ’ 10 10p = 90 Dividing both sides by 10 10๐‘/10 = 90/10 p = 9 Ex 4.2, 4 Solve the following equations: (c) ๐‘/4 = 5๐‘/4 = 5 Multiply both sides by 4 ๐‘/4 ร— 4 = 5 ร— 4 p = 20 Ex 4.2, 4 Solve the following equations: (d) (โˆ’๐‘)/3 = 5(โˆ’๐‘)/3 = 5 Multiplying both sides by 3 (โˆ’๐‘)/3 ร— 3 = 5 ร— 3 โˆ’p ร— 1 = 15 โˆ’p = 15 Multiplying both sides by โˆ’1 โˆ’p ร— โˆ’1 = 15 ร— โˆ’1 p = โˆ’15 Ex 4.2, 4 Solve the following equations: (e) 3๐‘/4 = 63๐‘/4 = 6 Multiplying both sides by 4 3๐‘/4 ร— 4 = 6 ร— 4 3p = 24 Diving both sides by 3 3๐‘/3 = 24/3 p = 8 Ex 4.2, 4 Solve the following equations: (f) 3s = โ€“9 Ex 4.2, 4 Solve the following equations: (g) 3s + 12 = 0 3s + 12 = 0 Subtracting both sides by 12 3s + 12 โˆ’ 12 = 0 ร— 12 3s = โˆ’12 Diving both sides by 3 3๐‘ /3 = (โˆ’12)/3 s = โˆ’4 Ex 4.2, 4 Solve the following equations: (h) 3s = 03s = 0 Diving both sides by 3 3๐‘ /3 = 0/3 s = 0 Ex 4.2, 4 Solve the following equations: (i) 2q = 62q = 6 Diving both sides by 2 2๐‘ž/2 = 6/2 q = 3 Ex 4.2, 4 Solve the following equations: (j) 2q โ€“ 6 = 02q โˆ’ 6 = 0 Adding 6 to both sides 2q โˆ’ 6 + 6 = 0 + 6 2q = 6 Diving both sides by 2 2๐‘ž/2 = 6/2 q = 3 Ex 4.2, 4 Solve the following equations: (k) 2q + 6 = 02q + 6 = 0 Subtracting both sides by 6 2q + 6 โˆ’ 6 = 0 โˆ’ 6 2q = โˆ’6 Diving both sides by 2 2๐‘ž/2 = (โˆ’6)/2 q = โˆ’3 Ex 4.2, 4 Solve the following equations: (l) 2q + 6 = 122q + 6 = 12 Subtracting both sides by 6 2q + 6 โˆ’ 6 = 12 โˆ’ 6 2q = 6 Diving both sides by 2 2๐‘ž/2 = 6/2 q = 3

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.