1. Chapter 4 Class 7 Simple Equations
  2. Serial order wise
  3. Examples

Example 5 - Chapter 4 Class 7 Simple Equations

Last updated at July 2, 2018 by

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  1. Chapter 4 Class 7 Simple Equations
  2. Serial order wise
    3. Examples
    Concept wise →
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Example 5 Solve: (a) 3n + 7 = 253n + 7 = 25 Subtracting 7 from both sides. 3n + 7 โˆ’ 7 = 25 โˆ’ 7 3n + 7 โˆ’ 7 = 25 โˆ’ 7 Dividing 3 both sides 3๐‘›/3 = 18/3 n = 6 3n + 7 = 25 Subtracting 7 from both sides. 3n + 7 โˆ’ 7 = 25 โˆ’ 7 3n + 7 โˆ’ 7 = 25 โˆ’ 7 Dividing 3 both sides 3๐‘›/3 = 18/3 n = 6 Example 5 Solve: (b) 2p โ€“ 1 = 23 2p โˆ’ 1 = 23 Adding 1 to both sides. 2p โˆ’ 1 + 1 = 23 + 1 2p = 24 Dividing 2 both sides 2๐‘/2 = 24/2 p = 12

Chapter 4 Class 7 Simple Equations
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.