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Example 5 (i) - Chapter 4 Class 7 Simple Equations
Last updated at March 16, 2023 by Teachoo
Examples
Example 1 (i)
Example 1 (ii) Important
Example 1 (iii) Important
Example 1 (iv)
Example 2 (i) Important
Example 2 (ii)
Example 2 (iii)
Example 2 (iv) Important
Example 3
Example 4 Important
Example 5 (i) You are here
Example 5 (ii) Important
Example 6
Example 7 (a)
Example 7 (b) Important
Example 8
Example 9 Important
Example 10 Important
Transcript
Example 5 Solve: (a) 3n + 7 = 253n + 7 = 25 Subtracting 7 from both sides. 3n + 7 β 7 = 25 β 7 3n + 7 β 7 = 25 β 7 Dividing 3 both sides 3π/3 = 18/3 n = 6 3n + 7 = 25 Subtracting 7 from both sides. 3n + 7 β 7 = 25 β 7 3n + 7 β 7 = 25 β 7 Dividing 3 both sides 3π/3 = 18/3 n = 6
