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Ex 4.1, 3 (i) - Chapter 4 Class 7 Simple Equations
Last updated at Sept. 11, 2021 by Teachoo
Transcript
Ex 4.1, 3 Solve the following equations by trial and error method: (i) 5p + 2 = 17 Putting p = 0 5p + 2 = 17 5(0) + 2 = 17 0 + 2 = 17 2 = 17 It is not true. ∴ p = 0 is not a solution. Putting p = 1 5p + 2 = 17 5(1) + 2 = 17 5 + 2 = 17 7 = 17 It is not true. ∴ p = 1 is not a solution. Putting p = 2 5p + 2 = 17 5(2) + 2 = 17 10 + 2 = 17 12 = 17 It is not true. ∴ p = 1 is not a solution. Putting p = 3 5p + 2 = 17 5(3) + 2 = 17 15 + 2 = 17 17 = 17 It is true. ∴ p = 3 is a solution
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Ex 4.1
Ex 4.1, 1
Ex 4.1, 2 Important
Ex 4.1, 3 (i) You are here
Ex 4.1, 3 (ii)
Ex 4.1, 4 (i) Important
Ex 4.1, 4 (ii)
Ex 4.1, 4 (iii)
Ex 4.1, 4 (iv)
Ex 4.1, 4 (v)
Ex 4.1, 4 (vi)
Ex 4.1, 4 (vii)
Ex 4.1, 4 (viii)
Ex 4.1, 4 (ix)
Ex 4.1, 5 (i) Important
Ex 4.1, 5 (ii)
Ex 4.1, 5 (iii)
Ex 4.1, 5 (iv)
Ex 4.1, 5 (v)
Ex 4.1, 5 (vi)
Ex 4.1, 5 (vii)
Ex 4.1, 5 (viii)
Ex 4.1, 6 (i) Important
Ex 4.1, 6 (ii)
Ex 4.1, 6 (iii)
Ex 4.1, 6 (iv)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.