# Ex 1.1, 2 - Chapter 1 Class 8 Rational Numbers

Last updated at June 22, 2018 by Teachoo

Last updated at June 22, 2018 by Teachoo

Transcript

Ex 1.1, 2 Write the additive inverse of each of the following.(i) 2/8 Additive inverse of 2/8 Check: Number + Additive inverse = 0 L.H.S = Number + Additive inverse = 2/8+(( 2)/8) = 0 = R.H.S Hence, ( 2)/8 is the additive inverse Ex 1.1, 2 Write the additive inverse of each of the following.(ii) ( 5)/9 Additive inverse of ( 5)/9 Check: Number + Additive inverse = 0 L.H.S = Number + Additive inverse = ( 5)/9+5/9 = 0 = R.H.S Hence, 5/9 is additive inverse of ( 5)/9. Ex 1.1, 2 Write the additive inverse of each of the following.(iii) ( 6)/( 5) Additive inverse of ( 6)/( 5) = ( )/ Check: Number + Additive inverse = 0 L.H.S = Number + Additive inverse = ( 6)/( 5)+(( 6)/5) = 6/5+(( 6)/5) = 0 = R.H.S Hence, ( 6)/5 is additive inverse of ( 6)/( 5) . Ex 1.1, 2 Write the additive inverse of each of the following.(iv) 2/( 9) Additive inverse of 2/( 9) = / Check: Number + Additive inverse = 0 L.H.S = Number + Additive inverse = 2/( 9) + 2/9 = ( 2)/9 + 2/9 = 0 = RHS Hence, 2/9 is additive inverse of 2/( 9) . Ex 1.1, 2 Write the additive inverse of each of the following.(v) 19/( 6) Additive inverse of 19/( 6) = 19/6 Check: Number + Additive inverse = 0 L.H.S = Number + Additive inverse = 19/( 6) + 19/6 = ( 19)/6 + 19/6 = 0 = R.H.S Hence, 19/6 is additive identify of 19/( 6)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.