Ex 1.1
Ex 1.1, 2
Ex 1.1, 3
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Last updated at April 16, 2024 by Teachoo
Ex 1.1, 1 Using appropriate properties find. (i) – 2/3 × 3/5 + 5/2−3/5 × 1/6 – 2/3 × 3/5 + 5/2−3/5 × 1/6 = – 2/3 × 𝟑/𝟓 −𝟑/𝟓 × 1/( 6) + 5/2 = 𝟑/𝟓 ((−2)/3−1/6)+ 5/2 = 3/5 ((−2 × 2 − 1)/6) + 5/2 = 3/5 ((−4 − 1)/6)+ 5/2 = 3/5 × ((−5))/6+ 5/2 = (−1)/2+5/2 = 4/2 = 2