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Ex 1.4, 7 - An elevator descends into a mine shaft at rate of 6 m/min

Ex 1.4, 7 - Chapter 1 Class 7 Integers - Part 2

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Ex 1.4, 7 An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach 350 m. Total distance elevator has to travel = Initial position final position = 10 ( 350) = 10 + 350 = 360 m Now, Elevator descends at rate 6m / min Elevator travels 6 m in = 1 minute Elevator travels 1 m in = 1/6 minute Elevator travels 360 m in = 1/6 360 minutes = 60 minutes = 1 hour It will take the elevator 1 hour.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.