Ex 1.4, 7 An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach 350 m.
Total distance elevator has to travel = Initial position final position
= 10 ( 350)
= 10 + 350
= 360 m
Now,
Elevator descends at rate 6m / min
Elevator travels 6 m in = 1 minute
Elevator travels 1 m in = 1/6 minute
Elevator travels 360 m in = 1/6 360 minutes
= 60 minutes
= 1 hour
It will take the elevator 1 hour.

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.