Ex 1.4, 7 An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach 350 m.
Total distance elevator has to travel = Initial position final position
= 10 ( 350)
= 10 + 350
= 360 m
Now,
Elevator descends at rate 6m / min
Elevator travels 6 m in = 1 minute
Elevator travels 1 m in = 1/6 minute
Elevator travels 360 m in = 1/6 360 minutes
= 60 minutes
= 1 hour
It will take the elevator 1 hour.

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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