What will be the smallest 3-digit number which divides 2, 4, 6 and leaves remainder 0?
Smallest Number which divides 2, 4, 6 and leaves remainder 0
= LCM of 2, 4, 6
= 12
We need to find the smallest 3-digit number which will divide 2, 4, 6
Smallest 3 digit number = 100
We divide 100 by 12
If we get 12 here, the remainder will be 0.
To get 12 we add (12 − 4) to number.
So remainder is 4
But we need to find a number where remainder is 0.
∴ Required number = 100 + (12 − 4)
= 100 + 8
= 108
So, 108 is the smallest 3 digit number divisible by 2, 4, 6
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.
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