Ex 3.7, 9 - Chapter 3 Class 6 Playing with Numbers
Last updated at August 14, 2026 by Teachoo
Statement questions on LCM
How to check if LCM is to be found or HCF
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Chapter 3 Class 6 Playing with Numbers
Concept wise
- Factors and Multiples
- Perfect number
- Prime and Composite Numbers
- Sum of prime numbers
- Prime numbers from 1 to 100
- Divisibility Tests - Divisibility by 5, 10, 2
- Divisibility Tests - Divisibility by 4, 8
- Divisibility Tests - Divisibility by 3, 6, 9
- Divisibility Tests - Divisibility by 11
- Divisibility Tests - All
- Common Multiples
- Common Factors
- More Divisibility Rules
- Factor Tree
- Prime Factorisation
- Highest Common Factor
- Lowest Common Multiple
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Statement questions on LCM
- Statement questions on HCF
Transcript
Let’s first find smallest number divisible by 18, 24, 32 Smallest number divisible by 18, 24, 32 = LCM of 18, 24, 32 LCM of 18, 24, 32 LCM = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288 ∴ 288 is the smallest number divisible by 18, 24, 32 Now, We need to find smallest 4-digit number divisible by 18, 24, 32 Smallest 4 digit number = 1000 we divide 1000 by 288 So remainder is 136 But we need to find a number where remainder is 0. Required number = 1000 + (288 − 136) = 1000 + 152 = 1152 So, 1152 is the smallest 4 digit number
