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Last updated at Jan. 3, 2019 by Teachoo
Transcript
Let’s first find smallest number divisible by 18, 24, 32 Smallest number divisible by 18, 24, 32 = LCM of 18, 24, 32 LCM of 18, 24, 32 LCM = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288 ∴ 288 is the smallest number divisible by 18, 24, 32 Now, We need to find smallest 4-digit number divisible by 18, 24, 32 Smallest 4 digit number = 1000 we divide 1000 by 288 So remainder is 136 But we need to find a number where remainder is 0. Required number = 1000 + (288 − 136) = 1000 + 152 = 1152 So, 1152 is the smallest 4 digit number
Statement questions on LCM
What is the smallest number when divided by numbers 2, 4, 6 gives remainder 0?
What is the smallest number when divided by numbers 2, 4, 6 gives remainder 7?
Example 14 Important
Ex 3.7, 8
Ex 3.7, 4
Ex 3.7, 9 Important You are here
Ex 3.7, 5
Example 13
Ex 3.7, 2
What will be the smallest 3-digit number which divides 2, 4, 6 and leaves remainder 0?
What will be the greatest 3-digit number which divides 2, 4, 6 and leaves remainder 0?
Ex 3.7, 6 Important
Statement questions on LCM
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