Ex 3.5, 6 - Chapter 3 Class 6 Playing with Numbers
Last updated at April 16, 2024 by Teachoo
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Chapter 3 Class 6 Playing with Numbers
Concept wise
- Factors and Multiples
- Perfect number
- Prime and Composite Numbers
- Sum of prime numbers
- Prime numbers from 1 to 100
- Divisibility Tests - Divisibility by 5, 10, 2
- Divisibility Tests - Divisibility by 4, 8
- Divisibility Tests - Divisibility by 3, 6, 9
- Divisibility Tests - Divisibility by 11
- Divisibility Tests - All
- Common Multiples
- Common Factors
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More Divisibility Rules
- Factor Tree
- Prime Factorisation
- Highest Common Factor
- Lowest Common Multiple
- Statement questions on LCM
- Statement questions on HCF
Transcript
Ex 3.5, 6 The product of three consecutive numbers is always divisible by 6. Verify this statement with the help of some examples.Let us find Product three consecutive numbers 1 × 2 × 3 2 × 3 × 4 3 × 4 × 5 4 × 5 × 6 5 × 6 × 7 = 210 10 × 11 × 12 = 1320 12 × 13 × 14 = 2184 13 × 14 × 15 = 2730 Let’s check if these numbers are divisible by 6 If a number is divisible by 6 it is divisible by 2 it is divisible by 3 We note that in all numbers Numbers ends with 0, 2, 4, 6, 8 ∴ It is divisible by 2 Sum of digits is divisible by 3 ∴ It is divisible by 3 Since all numbers are divisible by 2 & 3 They will be divisible by 6 ∴ Product of any three consecutive numbers is divisible by 6
