Question 5 In given figure, ST RQ, PS = 3 cm and SR = 4 cm. Find the ratio of the area of PST to the area of PRQ. Given: ABC ST II RQ PS = 3 cm, SR = 4cm To find : ( )/( ) Proof: In PRQ & PST, QPR = TPS PRQ = PST PRQ ~ PST Now, we know that in similar triangles, Ratio of area of triangle is equal to ratio of square of corresponding sides ( )/( )=( / )^2 ( )/( )=( /( + ))^2 ( )/( )=(3/(3 + 4))^2 ( )/( )=(3/7)^2 ( )/( )=9/49 Required Ratio = 9 : 49 (Putting PS = 3 cm, SR = 4 cm)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.

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