Question 5 In given figure, ST RQ, PS = 3 cm and SR = 4 cm. Find the ratio of the area of PST to the area of PRQ. Given: ABC ST II RQ PS = 3 cm, SR = 4cm To find : ( )/( ) Proof: In PRQ & PST, QPR = TPS PRQ = PST PRQ ~ PST Now, we know that in similar triangles, Ratio of area of triangle is equal to ratio of square of corresponding sides ( )/( )=( / )^2 ( )/( )=( /( + ))^2 ( )/( )=(3/(3 + 4))^2 ( )/( )=(3/7)^2 ( )/( )=9/49 Required Ratio = 9 : 49 (Putting PS = 3 cm, SR = 4 cm)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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