CBSE Class 10 Sample Paper for 2018 Boards
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CBSE Class 10 Sample Paper for 2018 Boards
Last updated at July 27, 2026 by Teachoo
This is a question of CBSE Sample Paper - Class 10 - 2017/18.
You can download the question paper here https://www.teachoo.com/cbse/sample-papers/
Transcript
Question 5 In given figure, ST RQ, PS = 3 cm and SR = 4 cm. Find the ratio of the area of PST to the area of PRQ. Given: ABC ST II RQ PS = 3 cm, SR = 4cm To find : ( )/( ) Proof: In PRQ & PST, QPR = TPS PRQ = PST PRQ ~ PST Now, we know that in similar triangles, Ratio of area of triangle is equal to ratio of square of corresponding sides ( )/( )=( / )^2 ( )/( )=( /( + ))^2 ( )/( )=(3/(3 + 4))^2 ( )/( )=(3/7)^2 ( )/( )=9/49 Required Ratio = 9 : 49 (Putting PS = 3 cm, SR = 4 cm)
