f: R R

f(x) = [x]

[x] is the greatest integer less than or equal to x

 

[0] = 0

[0.0001] = 0

[0.1] = 0

[0.9999] = 0

[1] = 1

 

[1.01] = 1

[1.2] = 1

[1.99] = 1

[1.9999999] = 1

[2] = 2

 

[2.0001] = 2

[2.2] = 2

[2.999] = 2

[3] = 3


For negative numbers

 

[–0.1]

Since it is greatest integer less than or equal to x

Integers less than – 0.1 = –1, –2, –3

Greatest Integer less than – 0.1 = –1

∴ [–0.1] = –1

 

[– 0.5]

Since it is greatest integer less than or equal to x

Integers less than – 0.5 = –1, –2, –3

Greatest Integer less than – 0.5 = –1

∴ [–0.5] = –1

 

[–0.999]

Since it is greatest integer less than or equal to x

Integers less than – 0.999 = –1, –2, –3

Greatest Integer less than – 0.999 = –1

∴ [–0.999] = –1

 

[–1]

[–1] = –1

 

[–1.1]

Since it is greatest integer less than or equal to x

Integers less than – 1.1 = –2, –3, –4

Greatest Integer less than –1.1 = –2

∴ [–1.1] = –2

 

[–1.999]

Since it is greatest integer less than or equal to x

Integers less than –1.999 = –2, –3, –4

Greatest Integer less than –1.999 = –2

∴ [–1.999] = –2

 

[–2]

[–2] = –2

 


Now, let us draw the graph

[0] = 0, [0.0001] = 0, [0.1] = 0, [0.9999] = 0, [1] = 1

So, for 0 ≤ x < 1, f(x) = 0

 

[1] = 1, [1.01] = 1, [1.2] = 1, [1.99] = 1, [1.9999999] = 1, [2] = 2

So, for 1 ≤ x < 2, f(x) = 1

 

[2] = 2, [2.0001] = 2, [2.2] = 2, [2.999] = 2, [3] = 3

So, for 2 ≤ x < 3, f(x) = 2

 

[–0.1] = –1, [–0.5] = –1, [–0.999] = –1, [–1] = –1

So, for –1 ≤ x < 0, f(x) = –1

 

[–1.1] = –1, [–1.999] = –2, [–2] = –2

So, for –2 ≤ x < –1, f(x) = –2


To summarise,

For 0 ≤ x < 1, f(x) = 0

For 1 ≤ x < 2, f(x) = 1

For 2 ≤ x < 3, f(x) = 2

For –1 ≤ x < 0, f(x) = –1

For –2 ≤ x < –1, f(x) = –2

Greatest Integer Function.jpg

 

Here,

Domain = All values of x = R

 

Range = All values of y

Since y will have integer values ( … –3, –2, –1, 0, 1, 2, 3, …)

Range = All Integers = Z

  1. Chapter 2 Class 11 Relations and Functions
  2. Concept wise
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 7 years. He provides courses for Mathematics and Science from Class 6 to 12. You can learn personally from here https://www.teachoo.com/premium/maths-and-science-classes/.
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