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Question 1 - Constructing Triangle - Given base, angle and sum of other 2 sides - Constructions
Last updated at August 14, 2026 by Teachoo
Constructing Triangle - Given base, angle and sum of other 2 sides
Constructions
Concept wise
- Constructing bisector of angle and perpendicular bisector
- Constructing angles - 60, 90, 45, 30 and others
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Constructing Triangle - Given base, angle and sum of other 2 sides
- Constructing Triangle - Given base, angle and difference of sides
- Constructing Triangle - Given sum of 3 sides and 2 base angles
Transcript
Question 1 Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm. Steps of Construction: Draw base BC of length 7 cm 2. Now, let’s draw ∠ B = 75° Let the ray be BX Check Ex 11.1, 4 (i) on how to construct 75° 3. Open the compass to length AB + AC = 13 cm. From point B as center, cut an arc on ray BX. Let the arc intersect BX at D 4. Join CD Now, we will draw perpendicular bisector of CD 6. Mark point A where perpendicular bisector intersects BD Join AC ∴ Δ ABC is the required triangle Now, we will draw perpendicular bisector of CD 6. Mark point A where perpendicular bisector intersects BD Join AC ∴ Δ ABC is the required triangle
