Question 5 - Constructing bisector of angle and perpendicular bisector - Constructions
Last updated at April 16, 2024 by Teachoo
Constructing bisector of angle and perpendicular bisector
Constructions
Concept wise
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Constructing bisector of angle and perpendicular bisector
- Constructing angles - 60, 90, 45, 30 and others
- Constructing Triangle - Given base, angle and sum of other 2 sides
- Constructing Triangle - Given base, angle and difference of sides
- Constructing Triangle - Given sum of 3 sides and 2 base angles
Transcript
Question 5 Construct an equilateral triangle, given its side and justify the construction.Let’s assume side of equilateral triangle is 5.5 cm In an equilateral triangle, all sides are equal So, our triangle looks like Let’s construct it Steps of construction 1. Draw a line segment AB of length 5.5 cm 2. Taking 5.5 cm as radius, and A as center, draw an arc. 3. Taking 5.5 cm as radius, and B as center, draw another arc. Let C be the point where the two arcs intersect Join AC and BC and label the sides Thus, Δ ABC is the required equilateral triangle Justification By construction, AB = AC = BC Since all sides are equal ∴ ∆ABC is an equilateral triangle. Thus, the Construction is justified. (Radius of equal arcs)
