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**
Ex 11.2, 2
**

Construct a tangent to a circle of radius 4 cm from a point on the concentric circle of radius 6 cm and measure its length. Also verify the measurement by actual calculation.

Tangents on the given circle can be drawn as follows.

- Draw a circle of 4 cm radius with centre as O on the given plane.
- Draw a circle of 6 cm radius taking O as its centre.
- Locate a point P on this circle and join OP.
- Bisect OP. Let M be the mid-point of OP
- Take M as its centre and MO as its radius, draw a circle. Let it intersect the given circle at the points Q and R.
- Join PQ and PR.

PQ and PR are the required tangents.

By measuring,

Lengths of PQ and PR is 4.47 m

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Finding lengths of PQ and PR
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Join OQ and OR

Since tangent is perpendicular to radius

∠ PQO = 90° and ∠ PRO = 90°

Thus, Δ PQO is a right angled triangle,

Also,

PO = radius of bigger circle = 6 cm

and OQ = radius of smaller circle = 4 cm

By Pythagoras theorem

PO2 = PQ2 + OQ2

62 = PQ2 + 42

36 = PQ2 + 16

PQ2 = 36 – 16

PQ2 = 20

PQ = √20 = √(5 ×4) = √4 × √5 = 2√5

PQ = 2 × 2.236

PQ = 4.47 cm

Similarly, PR = 4.47 cm

**
Justification:
**

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We
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need to prove that PQ and PR are the tangents to the circle.
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Join OQ and OR.

∠PQO is an angle in the semi-circle

of the blue circle

And we know that angle in a

semi-circle is a right angle.

∴ ∠PQO = 90°

⇒ OQ ⊥ PQ

Since OQ is the radius of the circle,

PQ has to be a tangent of the circle.

Similarly, PR is a tangent of the circle.

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