Example 3 - Chapter 12 Class 12 Linear Programming (Term 1)
Last updated at Feb. 17, 2020 by Teachoo
Last updated at Feb. 17, 2020 by Teachoo
Transcript
Example 3 Solve the following problem graphically: Minimise and Maximise Z = 3x + 9y subject to the constraints: x + 3y ≤ 60 x + y ≥ 10 x ≤ y x ≥ 0, y ≥ 0 Maximize Z = 3x + 9y Minimize Z = 3x + 9y Subject to, x + 3y ≤ 60 x + y ≥ 10 x ≤ y x ≥ 0, y ≥ 0 ∴ Z = 60 is minimum at (5, 5) Also, Z is maximum at two points (15, 15) & (0, 20) ∴ Z = 180 is maximum at all points joining (15, 15) & (0, 20)
Linear equations given - Bounded
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