Ex 12.1, 9 - Maximise Z = -x + 2y subject to x > 3, x + y > 5 - Linear equations given - Unbounded

Slide26.PNG
Slide27.PNG Slide28.PNG

  1. Chapter 12 Class 12 Linear Programming
  2. Serial order wise
Ask Download

Transcript

Ex 12.1, 9 Maximise Z = – x + 2y, subject to the constraints: x ≥ 3, x + y ≥ 5, x + 2y ≥ 6, y ≥ 0 Maximize Z = – x + 2y Subject to, x ≥ 3 x + y ≥ 5 x + 2y ≥ 6 y ≥ 0 But as the feasible region is unbounded Hence 1 can or cannot be the maximum value of z So, we need to graph Inequality –x + 2y > 1 Since feasible region of –x + 2y > 1 has some points in common. So there is no maximum value for Z subject to given constraints.

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.